元组
构建元组
a = ('a', 'b', 'c')
# from a list or any other iterable collection
c = tuple([1, 3, 5]) # (1, 3, 5)
遍历元素
a = ("fig", "mango", "watermelon")
for e in a:
print(e)
解构元组
a = ("fig", "mango", "watermelon")
item1, item2, item3 = a
print(item1) # fig
print(item2) # mango
print(item3) # watermelon
检查元素是否存在
a = ("fig", "mango", "watermelon")
print("fig" in a) # True
print("cherry" in a) # False
元组常用方法
count 计数
a = ("fig", "mango", "fig", "watermelon", "fig")
print(a.count("fig")) # 3
index 索引
a = ("fig", "mango", "fig", "watermelon", "fig")
print(a.index("watermelon")) # 3
代码挑战
修改编辑器中代码,构建如右元组:
(1, 'hello', ['a', 'b'], {'a': 1, 'b': 2}, False, (1, 2, 3))
。
Loading...
> 此处输出代码运行结果